There are more
common and, it has to be said, simpler ways of folding an equilateral triangle
from a rectangle. But this method makes use of the unique properties of “A”
paper.

The first stage is
to make a “measuring piece” that will be used to find out where to fold the
rectangle.
Fold a rectangle in
half along its diagonal.
This fold has a
length of √3. ( Check this using
Pythagoras’ Theorem)
Now
take this new shape and fold in the end so that fold passes through the first
peak.
Repeat
this with the other end of the diagonal and you will find that the original
diagonal has been divided into 3 equal parts. The length of the base
is now √3/3
Is this just roughly correct or can
you prove that this method of folding does indeed exactly trisect the
diagonal of the “A” rectangle?
Take
another sheet of A paper equal to the original.
Place the
“measuring piece” alongside and use it to measure off where the fold must come.
Mark and crease.
Repeat on the other
side using partly unfolded “measuring piece”.
Having
scored along the creases, fold to give an equilateral triangle.

This creates an
equilateral triangle of height 1 unit. In fact it is the largest equilateral
triangle that can be created from this rectangle.
For patterns and
tessellations with this triangle click here